Arithmetic of Functions problem
Open ended

Answer: (gºh)(25)=2
Step-by-step explanation:
1. This exercise is about Composition of functions, then you have:
2. Then, you have that
(gºh)(25)[tex]=g(h(x))=\sqrt{x}-3[/tex]
3. Now, you must substitute 25 into the function, as you can see below:
(gºh)(25)[tex]=\sqrt{25}-3[/tex]
4. Simplify the fucntion.
5. Therfore, you obtain:
(gºh)(25)[tex]=5-3=2[/tex]
Answer:
(g°h)(25) = 2
Step-by-step explanation:
We have given two functions.
Firstly, we have to find two composition of two functions and secondly, we have to find (g°h)(25).
g(x) = x-3 and h(x) = √x
(g°h)(x) = g(h(x))
Putting given values in above formula,we have
(g°h)(x) = g(√x)
(g°h)(x) = √x-3
Putting x = 25 in above equation, we get
(g°h)(25) = √25-3
(g°h)(25) = 5-3
(g°h)(25) = 2