dan3376 dan3376
  • 08-02-2019
  • Mathematics
contestada

how do I solve this problem?

how do I solve this problem class=

Respuesta :

gmany
gmany gmany
  • 13-02-2019

Answer:

[tex]\large\boxed{AB=10}[/tex]

Step-by-step explanation:

[tex]\text{The Pythagorean theorem:}\\\\hypotenuse^2=leg^2+leg^2\\\\\text{We have}\\\\leg=6\\leg=8\\hypotenuse=AB\\\\\text{substitute:}\\\\AB^2=6^2+8^2\\\\AB^2=36+64\\\\AB^2=100\to AB=\sqrt{100}\\\\AB=10[/tex]

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