What is the surface area of the regular pyramid given below ?

Answer:
Option C [tex]207\ units^{2}[/tex]
Step-by-step explanation:
we know that
the surface area of a pyramid is equal to
[tex]SA=B+LA[/tex]
where
B is the area of the base
LA is the lateral area
The area of the base B is
[tex]B=9*9=81\ units^{2}[/tex]
The lateral area is equal to
[tex]LA=4*(1/2)(9*7)=126\ units^{2}[/tex]
the surface area is equal to
[tex]SA=81+126=207\ units^{2}[/tex]
Answer:
Choice C is correct answer.
Step-by-step explanation:
We have to find the surface area of of regular pyramid.
From given diagram , we observe that
Base = 9 units height = 7 units
The formula for total surface area of pyramid is
T.S.A = L.S.A + B
Total surface area of regular pyramid is sum of Lateral surface area and area of base.
L.S.A = 1/2pl where p is perimeter and l is height.
B = s² is area of base where s is base.
Hence, T.S.A = 1/2pl+ s²
Firstly, we have to find the perimeter.
p = 4s
p = 4(9) = 36 units
T.S.A = 1/2(36)(7)+(9)²
T.S.A = (18)(7) + 81
T.S.A = 126+81
T.S.A = 207 units.
Hence, the surface area of regular pyramid of 207 units.