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A gas isn’t heated from 298 k to 367 k while it’s volume changes from 2.5 L to 3.9 L. If the initial pressure of the gass is 1.1 atm , what is the final pressure of the gass

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This problem can be solved using one of the different gas laws, which is shown below:


PV/T


Given:


P1 = 1.1 atm

V1 = 2.5 L

T1 = 298 K


P2 = ?

V2 = 3.9 L

T2 = 367 K


Substituting the given:


P1V1/T1 = P2V2/T2


(1.1 * 2.5)/298 = (P2 * 3.9)/367

P2 = 0.868 atm


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Answer:

0.8684 atm

Explanation:

Using combined gas equation,

PV / T = k

P1*V1 / T1 = P2*V2 / T2

P1 = 1.10 atm

P2 = ?

V1 = 2.5L

V2 = 3.9L

T1 = 298k

T2 = 367k

P1*V1 / T1 = P2*V2 / T2

Making P2 the subject of formula;

P2 = P1*V1*T2 / V2*T1

P2 = 1.1*2.5*367 / 3.9*298

P2 = 1009.25 / 1162.2

P2 = 0.8684 atm

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