The answer is: 3.99g
First, we need to look for the Argon molecular mass:
[tex]Ar=39.948 g/mol[/tex]
Then, we must remember that 1 mol of an element is equal to [tex]6.022x10^{23} atoms[/tex] of the same element.
So,
To know what is the mass of [tex]6.022x10^{22}[/tex] atoms of Ar, we need to do the following calculations:
[tex]6.022x10^{22}*\frac{39.948g}{1mol} *\frac{1mol}{6.022x10^{23}} =3.99g[/tex]
So the mass of [tex]6.022x10^{22}[/tex] atoms of Argon is 3.99g.
Have a nice day!
3.99grams is the mass of argon 6.02 × 10²² atoms of argon.
In one mole of any substance 6.023 × 10²³ no. of atoms of that substance will present, i.e. 1 mole = 6.023 × 10²³ atoms
In question given that, no. of atoms of Argon = 6.02 × 10²²
Mole of argon in which 6.02 × 10²² atoms will present = 6.02×10²²atoms/6.023 × 10²³ atoms/mole
Mole of argon in which 6.02 × 10²² atoms will present = 0.099 mole
Now mass of argon can be calculated by using the below formula:
n =W/M, where
W = required mass = to find ?
M = molar mass of argon = 39.948g/mole
n = mole of argon
W = 0.099mole × 39.948g/mole = 3.99grams.
Hence, 3.99grams is the mass of argon.
To know more about moles, visit the below link:
https://brainly.com/question/15356425
