Hi there!

Thanks for stopping by. Can you help me with this Applied Calculus homework? #2 and #4, I can do the rest.

Thansk!

Hi there Thanks for stopping by Can you help me with this Applied Calculus homework 2 and 4 I can do the rest Thansk class=

Respuesta :

2. The plot represents a function that is continuous at [tex]x=a[/tex] - that is, there are no breakages in plotted curve - so

[tex]\displaystyle\lim_{x\to a}f(x)=f(a)=b[/tex]

4. Unlike in (2), there is a jump discontinuity which makes the limit as [tex]x\to a[/tex] non-existent.