Answer:
72 g
Step-by-step explanation:
a) Balanced equation
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 16.04 18.02
CH₄ + 2O₂ ⟶ CO₂ + 2H₂O
m/g: 32
(b) Mass of H₂O
(i) Calculate the moles of CH₄
n = 32 g CH₄ × (1 mol CH₄/16.04 CH₄)
= 2.00 mol CH₄
(ii) Calculate the moles of H₂O
The molar ratio is (2 mol H₂O /1 mol CH₄)
n = 2.00 mol CH₄ × (2 mol H₂O /1 mol CH₄)
= 3.99 mol H₂O
(iii) Calculate the mass of H₂O
m = 3.99 mol H₂O × (18.02 g H₂O /1 mol H₂O)
m = 72 g H₂O
The reaction produces 72 g H₂O.
