Which of the following shows that △PQS≅△RQS, when x=6? ANSWER QUICKLY PLEASE!!

Answer:
The second one
Step-by-step explanation:
x+6=2x (picture shows)
x=6 (algebra)
3x+1=19
2x+7=19
PQ=QR
SQ=SQ
SAS
The required congruency rule to prove △PQS≅△RQS is SAS congruency rule. Option B is correct.
Given:
The value of x is 6.
It is required to prove that △PQS≅△RQS.
Now, put the value of x=6 in the dimensions shown in the given figure:
[tex]PQ=3x+1\\PQ=19\\RQ=2x+7\\RQ=19\\\angle PQS=(x+3)^{\circ}\\=9^{\circ}\\\angle RQS=(2x)^{\circ}\\=9^{\circ}[/tex]
From the above values, it can be concluded in triangle PQS and RQS that,
[tex]PQ=RQ\\\angle PQS=\angle RQS\\SQ=SQ[/tex]
So, by using SAS congruency rule, △PQS≅△RQS.
Therefore, the required congruency rule to prove △PQS≅△RQS is SAS congruency rule. Option B is correct.
For more details, refer to the link:
https://brainly.com/question/19883734