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Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what is the temperature of the gas?

Respuesta :

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

[tex]V\propto T[/tex]    (At constant pressure and number of moles)

[tex]V=kT[/tex]

Given : V= 6.0 L

k= 0.020 L/K

T=?

[tex]6.0=0.020LK^{-1}\times T[/tex]

[tex]T=300 K[/tex]

Thus temperature of the gas is 300 K.

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