Respuesta :
Answer: [tex]Al_{1}P_{1}O_{4}[/tex]
Solution : Given,
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of Al = 22.1 g
Mass of P = 25.4 g
Mass of O = 52.5 g
Step 1 : convert given masses into moles.
Moles of Al =[tex] \frac{\text{ given mass of Al}text{ molar mass of Al}}= \frac{22.1g}{27g/mole}=0.8moles [/tex]
Moles of P = \frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{25.4g}{31g/mole}=0.8moles [/tex]
Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{52.5g}{16g/mole}=3.2moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Al = [tex]\frac{0.8}{0.8}=1[/tex]
For P = [tex]\frac{0.8}{0.8}=1 [/tex]
For O =[tex]\frac{3.2}{0.8}=4[/tex]
The ratio of Al: P : O= 1 : 1 : 4
Hence the empirical formula is [tex]Al_{1}P_{1}O_{4}[/tex]
