contestada

write the equation in general form of a line with a slope of -1/3 and y intercept of 10/3

10x+3y-1=0
x+3y+10=0
x+3y-10=0
10x-3y-1=0

Respuesta :

Answer:

[tex]x + 3y -10 = 0[/tex]

Step-by-step explanation:

Begin by writing the equation of the line in slope intercept form, y=mx+b.

Substitute m= -1/3 and b = 10/3.

[tex]y = -\frac{1}{3}x + \frac{10}{3}[/tex]

Convert to general from by moving both -1/3x and 10/3 to the other side of the equal sign. Then multiply the entire equation by 3 to clear the fractions.

[tex]\frac{1}{3}x + y - \frac{10}{3} = 0\\\\3(\frac{1}{3}x + y - \frac{10}{3} = 0)\\\\x + 3y -10 = 0[/tex]