1. Amperes, is the SI unit (also a fundamental unit) responsible for current.
2. [tex]I = \frac{q}{t}[/tex] Δq over Δt technically
Rearrange for Δq
I x Δt = Δq
1.5mA x 5 = Δq
Δq = 0.0075
Divide this by the fundamental charge "e"
Electrons: 0.0075 / 1.60 x 10^-19
Electrons: 4.6875 x 10^16 or 4.7 x 10^16
3. So we know that the end resistances will be equal so:
ρ = RA/L
ρL = RA
ρL/A = R
Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper
[tex]\frac{p1L1}{A1} = \frac{p2L2}{A2}\\[/tex]
We are looking for L2 so we can isolate using algebra to get:
[tex]\frac{A2(\frac{P1L1}{A1}) }{P2} = L2[/tex]
If you fill in those values you get 0.0205
or 2.05 cm
