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The bolts on the cylinder head of an engine require tightening to a torque of 108Nm. if she is using a wrench that is 30.0 cm long, what force must the mechanic exert to achieve this? How would the force needed to change if she used a 60.0cm wrench

Respuesta :

1. 360 N

Explanation:

The torque is given by:

[tex]M = Fd[/tex]

where

F is the force exerted

d is the distance between the point of application of the force and the centre of rotation

In this problem, we know:

M = 108 Nm is the torque

d = 30.0 cm = 0.30 m is the distance

So, we can re-arrange the equation to find the force exerted:

[tex]F=\frac{M}{d}=\frac{108 Nm}{0.30 m}=360 N[/tex]

2. 180 N

Explanation:

We can use the same formula used for the 1st part of the problem, but this time we have:

M = 108 Nm is the torque

d = 60.0 cm = 0.60 m is the distance

so, the force needed to be exerted is

[tex]F=\frac{M}{d}=\frac{108 Nm}{0.60 m}=180 N[/tex]