Respuesta :
Answer:
A, C, D
Step-by-step explanation:
we know that
If two numbers have a sum of zero, then we say they are additive inverses
so
case A)
Sum the polynomials;
They are additive inverses
case B)
Sum the polynomials;
They are not additive inverses
case C)
Sum the polynomials;
They are additive inverses
case D)
Sum the polynomials;
They are additive inverses
case E)
Sum the polynomials;
They are not additive inverses
Answer:
x^2 + 3x – 2; x^2 – 3x + 2
6z^5 + 6z^5 – 6z^4; (–6z^5) + (–6z^5) + 6z^4
x – 1; 1 – x
Step-by-step explanation:
To select the polynomial that has additive inverse, we check the sign of each term. each term has different sign then it has additive inverse
x^2 + 3x – 2
–x^2 – 3x + 2 (sign of all terms are different so correct additive inverse)
–y^7 – 10
–y^7 + 10 (sign of y^7 is same so it is not correct additive inverse)
6z^5 + 6z^5 – 6z^4
(–6z^5) + (–6z^5) + 6z^4 (sign of all terms are different so correct additive inverse)
x – 1
1 – x
-x +1 (sign of all terms are different so correct additive inverse)
(–5x2) + (–2x) + (–10)
5x2 – 2x + 10 (sign of -2x is same so it is not correct additive inverse)