Answer:
4.84 x 10²⁴ atoms.
Explanation:
- Firstly, we need to calculate the no. of moles of carbon tetrachloride (CCl₄).
- n = mass / molar mass = (310 g) / (153.82 g/mol) = 2.015 mol.
- Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³)
∴ The no. of carbon tetrachloride (CCl₄) molecules = no. of moles x NA = (2.015 mol) (6.022 x 10²³) = 1.21 x 10²⁴ molecules.
- Each molecule of carbon tetrachloride (CCl₄) contains 4.0 atoms of chlorine.
∴ The no. of chlorine atoms in 310 g of carbon tetrachloride (CCl₄) = 4 x 1.21 x 10²⁴ = 4.84 x 10²⁴ atoms.
