Answer:
Since, the length of one eraser = [tex]1\frac{1}{3}\text{ Inches}=\frac{4}{3}[/tex]
Also, the length of one pen = 4 × the length of one eraser
[tex]\text{The length of one pen} = 4\times \frac{4}{3}[/tex]
[tex]=\frac{16}{3}=5\frac{1}{3}\text{ inches}[/tex]
Thus, the length of one pen is 16/3 inches.
Solution by the bar model :
Take 4 boxes representing the [tex]1\frac{1}{3}\text{ inches}[/tex],
Add the total value of the boxes
[tex]= 1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}[/tex]
[tex]= 1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}[/tex]
[tex]=4 + \frac{4}{3}[/tex]
[tex]=4 + 1 + \frac{1}{3}[/tex]
[tex]= 5 + \frac{1}{3}[/tex]
[tex]=5\frac{1}{3}\text{ inches }[/tex]
