What is the area of this figure?

Answer:
54 units squared
Step-by-step explanation:
You have to divide the shape into simpler shapes such as rectangles and triangles that you can easily find the area of. Then, add those areas together. I divided it into one rectangle and three triangles.
Rectangle 1: length=7 width=6 6(7)=42
Triangle 1: base=6 height=2 1/2(6)2=6
Triangle 2: base=3 height=2 1/2(3)2=3
Triangle 3: base=6 height=1 1/2(6)1=3
Area= R1+T1+T2+T3= 42+6+3+3= 54 units squared
The area of the given figure is 53.5 square units
The given irregular figure can be decomposed into a trapezium below and two small triangles at the top.
Get the area of the trapezium:
Area of the trapezium = 1/2(a+b)h
Area of the trapezium = 1/2(9+7)6
Area of the trapezium = 8 * 6
Area of the trapezium = 48 square units
Area of the two triangles = 0.5(BH) + 0.5(bh)
Area of the two triangles = 0.5(1)(5) + 0.5(2)(3)
Area of the two triangles = 2.5+ 3
Area of the two triangles = 5.5 square units
Area of the figure = 48 + 5.5
Area of the figure = 53.5 square units
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