What is the equation of the line in slope-intercept form that is perpendicular to the line y =3/4 x – 2 and passes through the point (–12, 10)?

Respuesta :

Answer:

[tex]y=-\frac{4}{3}x-6[/tex]

Step-by-step explanation:

Perpendicular lines have slopes which are negative reciprocals of each other. The slope of the line y=3/4x-2 is 3/4. The slope perpendicular to it is -4/3.

Using m=-4/3, substitute it and (-12,10) into the point slope form and simplify to find the y-intercept.

[tex]y-y_1 = m(x-x_1)\\y-10=-\frac{4}{3}(x--12)\\y-10=-\frac{4}{3}(x+12)\\y-10=-\frac{4}{3}x-16\\y=-\frac{4}{3}x-6[/tex]