Answer:
15 360 people in State A and 58 560 in State B
Step-by-step explanation:
We have two conditions:
(1) A + B = 73 920
(2) B = 3A + 12 480
Solve the system of equations. Substitute (2) into (1).
A + 3A + 12 480 = 73 920 Subtract 12 480 from each side
4A = 61 440
(3) A = 15 360 Substitute (3) into (2)
B = 3×15 360 + 12 480
= 46 080 + 12 480
= 58 560
There are 15 360 people in State A and 58 560 in State B.
Check:
(1) 15 360 + 58 560 = 73 920 (2) 58 560 = 3×15 360 + 12 480
73 920 = 73 920 58 560 = 46 080 + 12 480
58 560 = 58 560
73,920 live in state A and state B.
15,360 people in State A and 58,560 in State B
Given:
Number of people of a certain community live in the country = 250,000
let:
Number of people live in state A = x
Number of people live in state B = y
[tex]x+y=73,920[/tex] ............(i)
The number of people of that community in state B is 12,480 more than three times the number in state A
[tex]y=3x+12,480[/tex] ..................(ii)
From (i) and (ii)
[tex]x+3x+12,480=73,929\\4x=73,920-12,480\\4x=61,440\\x=\frac{61,440}{4}[/tex]
[tex]x=15,360[/tex] Peoples.
Put x = 15,360 in (i)
[tex]15,360+y=73,920\\y=73,920-15,360\\y=58,560[/tex]
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