Answer:
[tex]\frac{x^{-8}}{x^{-7}}=x^{-1}[/tex]
Step-by-step explanation:
In division of powers with the same base, we must subtract the exponent of the denominator from the exponent of the numerator:
[tex]\frac{a^{m}}{a^{n}}=a^{m-n}[/tex]
Then applying this to the problem:
[tex]\frac{x^{-8}}{x^{-7}}=x^{-8-(-7)}[/tex]
Eliminating the parentheses:
[tex]\frac{x^{-8}}{x^{-7}}=x^{-8+7}\\ \frac{x^{-8}}{x^{-7}}=x^{-1}[/tex]
