Respuesta :

14a

[tex] \frac{2}{3x - 2c} + ( - ( \frac{3}{2x - 3c} )) = \frac{7}{2c} [/tex]

[tex] \frac{2}{3x - 2c} - \frac{3}{3x - 2c} = \frac{7}{2c} [/tex]

[tex] \frac{2 - 3}{3x - 2c} = \frac{7}{2c} [/tex]

[tex] \frac{ - 1}{3x - 2c} = \frac{7}{2c} [/tex]

Next, cross-multiply.

[tex] - 2c = 21x - 14c[/tex]

[tex]12c = 21x[/tex]

[tex]x = \frac{7}{4} c= 1 \frac{3}{4} c[/tex]