Answer:
The numbers are [tex]10[/tex] and [tex]4[/tex]
Step-by-step explanation:
Let
x-----> one number
y----> the other number
we know that
[tex]x+y=14[/tex] ------> equation A
[tex]x=3y-2[/tex] -----> equation B
Substitute equation B in equation A and solve for y
[tex]3y-2+y=14[/tex]
[tex]4y=14+2[/tex]
[tex]y=16/4=4[/tex]
Find the value of x
[tex]x=3(4)-2=10[/tex]