Answer:
C
Step-by-step explanation:
Jesse says that the period of the graph is triple that of sin x. He is correct stating this. But he is incorrect stating that the equation of the graph is f (x) 3sin x, because the graph of the function f(x)=3sin x has an amplitude 3 whereas the graph of the function y=sin x has an amplitude 1.
A. The period of the function y=sin x is 2π and the period of the function with given graph is 6π. Thus, this option is false because 6π is not doubled 2π.
B. The period of the function y=sin x is 2π, so the frequence of its graph is triple that of given function. Since this statement is inverse to the option B, this option is false.
C. The period of the function f(x)=sin x/3 is [tex]T=\dfrac{2\pi}{\frac{1}{3}}=6\pi,[/tex] so this option is true.
D. False, see explanation above.
