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In the previous question, you used the Hardy-Weinberg equation to determine the frequencies of the genotypes for HH, Hh, and hh, given gene frequencies of H = 0.2 and h = 0.8. These frequencies were: HH = 0.04 Hh = 0.32 hh = 0.64 Now, determine the expected numbers of each organism in the population (total size = 150): Number of HH = Number of Hh = Number of hh =

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If frequencies are: HH = 0.04 Hh = 0.32 hh = 0.64, this expressed in the percentage is 4%, 32% and 64%  (4+32+64=100) respectively. If the total number of organisms in population is 150 then:  

Number of organisms with HH genotype is 0.4*150= 6

Number of organisms with Hh genotype is 0.32*150=48

Number of organisms with hh genotype is 0.64*150=96

6+48+96=150

emmadennison

Answer:

HH- 6

Hh- 48

hh-96

Explanation:

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