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Two factory plants are making TV panels. Yesterday, Plant A produced 2000 fewer panels than Plant B did. Five percent of the panels from Plant A and 4% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 1070 defective pannels?

Respuesta :

sqdancefan

Answer:

  13,000 panels

Step-by-step explanation:

Let "a" and "b" represent the numbers of panels produced by Plant A and Plant B, respectively. The problem statement tells us ...

  a = b -2000

  .05a +.04b = 1070

Substituting the first equation into the second, we get ...

  .05(b -2000) + .04b = 1070

  .09b = 1170 . . . . . . . simpify, add 100

  1170/0.09 = b = 13,000 . . . . . divide by the coefficient of b

Plant B produced 13,000 panels yesterday.

fichoh

The number of panels produced by Plant B obtained using a system of linear equations is 13000

Setting up the equation as follows :

Let ;

panels produced by Plant B = b

Panels produced by Plant A , a = b - 2000 - - - - (1)

Total Number of defective panels :

0.05a + 0.04b = 1070 - - - - - (2)

From (1) :

0.05(b - 2000) + 0.04b = 1070

0.05b - 100 + 0.04b = 1070

0.09b = 1070 + 100

0.09b = 1170

b = 1170/0.09

b = 13000

Therefore, plant B produced 13000 panels

Learn more :https://brainly.com/question/11949421

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