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The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard form below.
________________ +x _____________ _____________=0

Respuesta :

MrsStrong

Answer:

[tex]x^2 + x -12[/tex]

Step-by-step explanation:

If the solutions are x=-4 and x=3, then it must have factors (x+4)(x-3). Assuming there is no GCF or leading coefficient other than 1, multiply with FOIL to find the standard form.

[tex](x+4)(x-3)\\x^2 + 4x -3x -12\\x^2 + x -12[/tex]

Answer:

Quadratic equation is x²  + x - 12  = 0.

Step-by-step explanation:

Given : The solutions to a certain quadratic equation are x = -4 and x = 3.

To find : Write the equation in standard form below.

Solution : We have given x = -4 and x = 3.

We can write the solution as x +4 = 0

x - 3 = 0.

Both the solution have GCF is 1

Then solution are (x +4)(x -3) = 0.

On distributing x over (x-3) and +4 over (x-3).

x(x-3) +4(x-3) = 0.

x² -3x +4x -12 = 0.

x²  + x - 12  = 0.

Then  quadratic equation is x²  + x - 12  = 0.

Therefore, Quadratic equation is x²  + x - 12  = 0.

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