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A rubber ball is dropped from a height of 128 feet. After each bounce, it rebounds one fourth of the distance it fell. How far does the ball fall on its third fall?

Respuesta :

5naka

first fall 128 feet,

second fall ¼•128=32 feet,

third fall ¼•32=8 feet

wegnerkolmp2741o

Answer:

8ft

Step-by-step explanation:

The drop is 128 ft

The first bounce is 1/4 the drop (2nd fall)

1/4(128) = 32 ft

The second bounce is 1/4 of the first bounce  (This would be considered the third fall)

1/4 (32) = 8 ft

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