Respuesta :

5naka

[tex] {h}^{ - 1} oh(x) = x \\ {h}^{ - 1} (4x + m) = x \\ 2k(4x + m) + \frac{5}{8} = x \\ 8kx + 2km + \frac{5}{8} = x[/tex]

k and m must satisfy 8k = 1 mean k = ⅛

and 2km+⅝=0 mean m = -5/2