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Suppose you are flying a kite that is 50 feet long. While flying there is a constants gust of wind that blows the kite to angle of 60 with the ground .How high, in feet is the kite above the ground?

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Answer:

The  kite forms a right angled triangle with hypotenuse of 50 ft. The height of the kite above the ground is the opposite of 60° angle.

Using the sine rule, Sin 60 = Height of the kite above the ground/Hypotenuse

Therefore, Height of the kite above the ground = Hypotenuse*Sin 60 = 50 *Sin 60 = 43.3 ft

I found this same question and answer (that was verified) on another Brainly post

Hope that helps! Happy v-day fam!

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