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kudzordzifrancis
ANSWER
[tex]y = x - 1[/tex]
EXPLANATION

We want to write an equation of the line that passes through the point

[tex](3,2)[/tex]
and perpendicular to

[tex]y = - x + 2[/tex]

The slope of this line is -1.

The slope of the line perpendicular to this line is
[tex]m = 1[/tex]
because the product of the two slopes should give us -1.


We now use the formula,


[tex]y-y_1=m(x-x_1)[/tex]

to find the required equation.


We substitute the values to obtain,


[tex]y - 2 = 1(x - 3)[/tex]

[tex]y - 2 = x - 3[/tex]


[tex]y = x - 3 + 2[/tex]

This implies that,


[tex]y = x - 1[/tex]
zainebamir540

Answer:

y = x-1 is equation of that is perpendicular to y = -x+2 and passes through (3,2)

Step-by-step explanation:

We have given a point and equation of a line.

Let (x,y)  = (3,2)  and y= -x+2

y = mx+c is equation of line where m is slope and c is y-intercept.

Here, m = -1

Perpendicular lines have slopes negative reciprocals to each other.

so, the slope of perpendicular line is 1.

y = x+c is equation of lines that is perpendicular to y = -x+2.

Now , we have to find the y-intercept of above equation using given point.

2 = 3+c

c = -1

hence, y = x-1 is equation of that is perpendicular to y = -x+2 and passes through (3,2).

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