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Denise is using a ladder to clean the outside of her second story windows. The ladder she is using is 24 feet long, and she puts the base of the ladder 13 feet away from the house in order to avoid her flower gardens. How high up the side of her house does the ladder reach? Round to the nearest tenth, if necessary.



Clay went for a run to prepare for a long distance race coming up. From his house, he ran 6 miles directly north and then 8 miles directly west. From there, he ran the diagonal distance back to his house. How many total miles did Clay run?

Respuesta :

Answer:

1) 20.2 feet

2) 24 miles

I am unsure if this is correct, but I used the Pythagorean theorem to solve your questions.

Step-by-step explanation:

1)

a^2 + b^2 = c^2

13^2 + b^2 = 24^2

b^2 = 24^2 - 13^2

b^2 = 576 - 169 = 407

b = √407 = 20.2

2)

6^2 + 8^2 = c^2

36 + 64 = c^2

100 = c^2

c = 10

10 + 6 + 8 = 24

A) Her ladder reaches 20.17 feet of the house.

B) Clay ran 24 miles.

A) Given that Denise is using a ladder to clean the outside of her second story windows, and the ladder she is using is 24 feet long, and she puts the base of the ladder 13 feet away from the house in order to avoid her flower gardens, to determine how high up the side of her house does the ladder reach, the Pythagorean theorem must be applied:

  • 13 ^ 2 + X ^ 2 = 24 ^ 2
  • 169 + X ^ 2 = 576
  • X ^ 2 = 576 - 169
  • X ^ 2 = 407
  • X = √407
  • X = 20.17

Therefore, her ladder reaches 20.17 feet of the house.

B) Since Clay went for a run to prepare for a long distance race coming up, and from his house, he ran 6 miles directly north and then 8 miles directly west, and from there, he ran the diagonal distance back to his house, to determine how many total miles did Clay run apply the Pythagorean theorem:

  • 6 ^ 2 + 8 ^ 2 = X ^ 2
  • 36 + 64 = X ^ 2
  • √100 = X
  • 10 = X
  • 6 + 8 + 10 = 24

Therefore, Clay ran 24 miles.

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