Answer:
{x = 0
, y = -6
Step-by-step explanation:
Solve the following system:
{y = -2 x - 6 | (equation 1)
{2 y = 4 x - 12 | (equation 2)
Express the system in standard form:
{2 x + y = -6 | (equation 1)
{-(4 x) + 2 y = -12 | (equation 2)
Swap equation 1 with equation 2:
{-(4 x) + 2 y = -12 | (equation 1)
{2 x + y = -6 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{-(4 x) + 2 y = -12 | (equation 1)
{0 x+2 y = -12 | (equation 2)
Divide equation 1 by 2:
{-(2 x) + y = -6 | (equation 1)
{0 x+2 y = -12 | (equation 2)
Divide equation 2 by 2:
{-(2 x) + y = -6 | (equation 1)
{0 x+y = -6 | (equation 2)
Subtract equation 2 from equation 1:
{-(2 x)+0 y = 0 | (equation 1)
{0 x+y = -6 | (equation 2)
Divide equation 1 by -2:
{x+0 y = 0 | (equation 1)
{0 x+y = -6 | (equation 2)
Collect results:
Answer: {x = 0
, y = -6
