Write the equation of the circle with center (3, 2) and (−6, −4) a point on the circle.
A) (x + 6)2 + (y + 4)2 = 13
B) (x + 3)2 + (y + 2)2 = 117
C) (x − 6)2 + (y − 4)2 = 13
D) (x − 3)2 + (y − 2)2 = 117

Respuesta :

Answer:

D. [tex](x-3)^2 + (y-2)^2 = 117[/tex]

Step-by-step explanation:

To write the equation of a circle, use the formula [tex](x-h)^2+(y-k)^2 = r^2[/tex] where the center of the circle is (h, k).

This means the equation is [tex](x-3)^2 + (y-2)^2 = r^2[/tex].

Find the radius r by finding the distance between (3,2) and (-6,-4) using the distance formula.

[tex]d = \sqrt{(-6-3)^2 + (-4-2)^2} =\sqrt{(-9)^2 + (-6)^2} =\sqrt{81+36} =\sqrt{117}[/tex]

Since the radius is √117 and therefore [tex]r^2 = 117[/tex].

The equation is [tex](x-3)^2 + (y-2)^2 = 117[/tex].

Answer:

D

Step-by-step explanation:

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