This problem can be solved using the Combined Gas Law. The formula for it is
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]
Let's go ahead and plug in the known values. Since pressure remains the same, it does not matter what value we plug in, so let's assume 1 atm for both sides.
[tex]\frac{(1 atm) (0.105 L)}{(105 K)} = \frac{(1 atm) (0.140 L) }{x K}[/tex]
Now, we just need to solve for the unknown. Start by simplifying the left side and right numerator.
0.001 = [tex]\frac{0.140 L}{x K}[/tex]
Multiply both sides by x.
0.001x = 0.140
Divide both sides by 0.001.
x = 140 K
Convert that to Celsius (K = C + 273)
140 = C + 273
C = -133
So, the volume of your gas will be 0.140 L at -133° C.
