Let the rate of walking in the evening be = x km/h
As Ed wants to walk at a rate if 1 km/h more in the morning, then rate in morning becomes = x+1 km/h
So, distance is 12 km, speed is x+1 km/h
[tex]time=\frac{distance}{speed}[/tex]
Total time is = 5 h 24 m or convert it into hours, it becomes 5.4 hours
Time in morning becomes =[tex]\frac{12}{x+12}[/tex]
Time in evening becomes =[tex]\frac{12}{x}[/tex]
So equation becomes= [tex]\frac{12}{x+1}+\frac{12}{x}=5.4[/tex]
Solving this quadratic equation, we get, x= -5/9 or x=4
As X cannot be negative so neglect -5/9.
Solving by using x=4, we get rate as x= 4+1 =5 km/h
Hence, rate in the morning is 5 km/h.
