part of an ancient coin was discovered it was measured to be only an 80° section of it was left. if the coin had a radius of 0.9 inches, what was the area of this sector​

part of an ancient coin was discovered it was measured to be only an 80 section of it was left if the coin had a radius of 09 inches what was the area of this s class=

Respuesta :

Area of sector = [tex] \frac{θ}{360} \times \pi {r}^{2} [/tex]
[tex] = \frac{80}{360} \times \pi \times {0.9}^{2} [/tex]
[tex] = \frac{80}{360} \times \pi \times 0.81[/tex]
[tex] = 0.565[/tex] inches
Answer has been been rounded off to 3 significant figures.

The area of the sector which is a part of an ancient coin and has 80 degree sections with 0.9 inches radius is 0.565 in².

What is the area of a circular sector?

The area of a circular sector is the total space occupied by it. The sector area is half of the product of the square of radius of the circle and the central angle.

It can be calculated as,

A(sector)=(πr²θ)/360

Here, (r) is the radius of the circle and (θ) is the central angle.

The 80° section of the coin was left. The coin had a radius of 0.9 inches. Thus, the area of this sector of coin is,

A(sector)=(π(0.9)²×80)/360

A(sector)=0.565 in²

Thus, the area of the sector which is a part of an ancient coin and has 80 degree sections with 0.9 inches radius is 0.565 in².

Learn more about the area of a circular sector here;

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