Answer: [tex]\bold{D)\ h^{-1}(x)=\dfrac{1}{6}(x-1)}[/tex]
Step-by-step explanation:
Inverse is when you swap the x's and y's and solve for y.
I am going to substitute h(x) with "y" while solving this problem.
[tex]y=6x+1\\\\\text{Swap the x's and y's}:\\x=6y+1\\\\\text{subtract 1 from both sides}:\\x-1=6y\\\\\text{Divide both sides by 6 to solve for y}:\\\dfrac{1}{6}(x-1)=y[/tex]
