Respuesta :

kudzordzifrancis

Answer:

False

Step-by-step explanation:

The given inequality is [tex]y\:<\:|x-2|+7[/tex]

We  substitute

[tex]x=3,y=8[/tex]

This implies that;

[tex]8\:<\:|3-2|+7[/tex]

[tex]8\:<\:|1|+7[/tex]

[tex]8\:<\:1+7[/tex]

[tex]8\:<\:8[/tex]

This is false.

8 is not less or greater than itself.

zainebamir540

Answer:

It is false, this ordered pair is not solution of inequality.

Step-by-step explanation:

We have given an inequality:

y < Ix-2I +7

We have to check is (3,8) is the solution of the inequality or not?

So, x = 3  , y = 8

y < Ix-2I +7

(8) < I(3) - 2I +7

8 < I1I + 7

8 < 1+7

8 < 8

8 is not less than 8.

So, it is false, this ordered pair is not solution of inequality.