Answer:
D. x^2 +3x -20)/(x+3)(x-5)(x+7)
Step-by-step explanation:
The given expression is [tex]\frac{x}{x^2 -2x -15} - \frac{4}{x^2 + 2x - 35}[/tex]
The denominators can be factorable.
= x / (x + 3)(x -5) - 4/(x-5)(x + 7)
Here (X+3)(x -5)(x + 7) is the Least Common Divisor.
= [tex]\frac{x(x+7) -4(x+5)}{(x+3)(x-5)(x+7)}[/tex]
= [x^2 + 7x -4x -20] / (x+3)(x-5)(X+7)
= (x^2 +3x -20)/(x+3)(x-5)(x+7)
Answer D. x^2 +3x -20)/(x+3)(x-5)(x+7)
Hope this will helpful.
Thank you.
