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The temperature of a chemical solution is originally 21^\circ\text{C}21 ? C21, degree, C. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ? C75, degree, C after 121212 minutes of heating.

Respuesta :

calculista

Answer:

The rate is [tex]4.5\frac{\°C}{min}[/tex]

Step-by-step explanation:

we know that

The formula to calculate the rate or slope between two points is equal to [tex]m=\frac{y2-y1}{x2-x1}[/tex]

Let

x----> the time in minutes

y-----> the temperature in Celsius degrees

we have

[tex]A(0,21)\ B(12,75)[/tex]

Substitute the values

[tex]m=\frac{75-21}{12-0}[/tex]

[tex]m=\frac{54}{12}=4.5\frac{\°C}{min}[/tex]

Answer:

T = 21 + 4.5x

This answer is right on Khan Academy! Hope it helps!