Answer:
e = 2/5
a = 5
b = √21
c = 2
Step-by-step explanation:
The first step is to write the given polar equation in standard form by dividing the numerator and denominator by 5;
[tex]r=\frac{\frac{21}{5} }{1-\frac{2}{5}costheta }[/tex]
The eccentricity of this conic section is thus 2/5, the coefficient of cos theta. Nevertheless, the eccentricity of a conic section can also be evaluated using the equation;
[tex]e=\frac{c}{a}[/tex]
This implies that ;
a = 5
c = 2
The value of b is determined using the relation;
[tex]b^{2}=a^{2}-c^{2} \\b=\sqrt{25-4} \\b=\sqrt{21}[/tex]
