Respuesta :
Definitions needed:
pH = -log[H^+]
pOH = -log[OH^-]
pH + pOH = 14
[H^+]*[OH^-] = 10^-14
(a) [H+] = 3.0 10-13 M
[OH ‾ ] = _____ M
Acidic, Basic, or Neutral?
[H^+]*[OH^-] = 10^-14
[OH^-] = (10^-14)/[H^+]
[OH^-] = (10^-14)/(3.0 10-13 M) = 0.033 M
That's a high concentration of [OH^-], so the solution is basic
(b) [OH ‾ ] = 3.0 10-7 M
[H+] = ______M
Acidic, Basic, or Neutral?
[H^+]*[OH^-] = 10^-14
[H^+]* = (10^-14)/[OH^-]
[H^+]* = (10^-14)/(3.0 10-7 M) = 3.33 x 10^-8
That would be a slightly basic solution (pH just higher than 7).
Explanation :
Solution for part (a) :
Concentration of [tex]H^+[/tex] = [tex]8.0\times 10^{-13}M[/tex]
As we know that,
[tex][H^+][OH^-]=10^{-14}[/tex]
Now put the value of concentration of hydrogen ion, we get concentration of hydroxide ion.
[tex](8.0\times 10^{-13})\times [OH^-]=10^{-14}[/tex]
[tex][OH^-]=1.25\times 10^{-2}M[/tex]
From this we conclude that, the concentration of hydroxide ion is more than the hydrogen ion that means the solution is basic in nature.
Solution for part (b) :
Concentration of [tex]OH^-[/tex] = [tex]4.0\times 10^{-7}M[/tex]
As we know that,
[tex][H^+][OH^-]=10^{-14}[/tex]
Now put the value of concentration of hydroxide ion, we get concentration of hydrogen ion.
[tex][H^+]\times (4.0\times 10^{-7})=10^{-14}[/tex]
[tex][H^+]=0.25\times 10^{-7}M[/tex]
From this we conclude that, the concentration of hydrogen ion is more than the hydroxide ion that means the solution is acidic in nature.
Solution for part (c) :
Concentration of [tex]OH^-[/tex] = [tex]5.0\times 10^{-3}M[/tex]
As we know that,
[tex][H^+][OH^-]=10^{-14}[/tex]
Now put the value of concentration of hydroxide ion, we get concentration of hydrogen ion.
[tex][H^+]\times (3.0\times 10^{-3})=10^{-14}[/tex]
[tex][H^+]=0.25\times 10^{-7}M[/tex]
From this we conclude that, the concentration of hydroxide ion is more than the hydrogen ion that means the solution is basic in nature.
Solution for part (d) :
Concentration of [tex]H^+[/tex] = [tex]8.0\times 10^{-5}M[/tex]
As we know that,
[tex][H^+][OH^-]=10^{-14}[/tex]
Now put the value of concentration of hydrogen ion, we get concentration of hydroxide ion.
[tex](8.0\times 10^{-5})\times [OH^-]=10^{-14}[/tex]
[tex][OH^-]=1.25\times 10^{-2}M[/tex]
From this we conclude that, the concentration of hydrogen ion is more than the hydroxide ion that means the solution is acidic in nature.
