Answer:
t = √(2d/g); 3.70 s
Step-by-step explanation:
The formula for the distance (d) travelled by a falling object in time (t) is
d = ½gt²
Multiply each side by 2 2d = gt²
Divide each side by g (2d/g) = t²
Take the square root of each side t = √(2d/g)
Data:
d = 220 ft
g = 32.17 ft·s⁻²
Calculation:
t = √ [(2 × 220)/32.17] = √13.68 = 3.70 s
The ball will hit the ground 3.70 s after it is released.
