Two rectangles are similar. One has a length of 11 cm and a width of 10cm, and the other has a width of 7cm. Find rhe length of the second rectangle. Round to the nearest tenth if necessary

Respuesta :

I believe the length of the second rectangle would be 7.7cm.

For this case we have to:

Let [tex]l_ {1} = 11 \ cm[/tex] and [tex]w_ {1} = 10[/tex] \ cm, respectively, the length and width of the first rectangle.

Let [tex]l_ {2}[/tex] and [tex]w_ {2} = 7 \ cm[/tex], respectively, the length and width of the second rectangle.

If both rectangles are similar, it is true that:

[tex]\frac {l_ {2}} {l_ {1}} = \frac {w_ {2}} {w_ {1}}[/tex]

Substituting:

[tex]\frac {l_ {2}} {11} = \frac {7} {10}\\\frac {l_ {2}} {11} = 0.7\\l_ {2} = 11 * 0.7\\l_ {2} = 7.7 \ cm[/tex]

Answer:

[tex]7.7 \ cm[/tex]