For this case we have that, by definition, a quadratic equation is of the form:
[tex]ax ^ 2 + bx + c = 0[/tex]
In addition, its roots are given by:
[tex]x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}[/tex]
If we have the following equation:
[tex]\frac {1} {4} x ^ 2 + 5 = 0[/tex]
So we have to:
[tex]a = \frac {1} {4}[/tex]
[tex]b = 0,[/tex] there is no term that accompanies x.
[tex]c = 5[/tex]
Asnwer:
[tex]a = \frac {1} {4}\\b = 0\\c = 5[/tex]
