For this case we have that the standard equation of a line is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut point with the y axis.
[tex]m = \frac {y2-y1} {x2-x1}[/tex]
We have the following points of the graph:
[tex](x1, y1) = (4,0)\\(x2, y2) = (0, -3)[/tex]
Substituting:
[tex]m = \frac {-3-0} {0-4}\\m = \frac {-3} {- 4}\\m = \frac {3} {4}[/tex]
We have:
[tex]y = \frac {3} {4} x + b[/tex]
To find the cut point we substitute a point:
[tex]0 = \frac {3} {4} (4) + b\\0 = 3 + b\\b = -3[/tex]
Thus, the equation is:
[tex]y = \frac {3} {4} x-3[/tex]
Answer:
[tex]y = \frac {3} {4} x-3[/tex]
