Check the picture below.
[tex]\bf \begin{cases} \qquad ~x\cdot tan(44^o)=y\\ (50+x)tan(40^o)=y \end{cases} \qquad \implies (x)tan(44^o)=(50+x)tan(40^o) \\\\\\ (x)tan(44^o)=(50)tan(40^o)+(x)tan(40^o) \\\\\\ (x)tan(44^o)-(x)tan(40^o)=(50)tan(40^o) \\\\\\ x[tan(44^o)-tan(40^o)]=(50)tan(40^o)[/tex]
[tex]\bf x=\cfrac{(50)tan(40^o)}{tan(44^o)-tan(40^o)} \implies \blacktriangleright x\approx 331.43 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ x\cdot tan(44^o)=y\implies 331.43\cdot tan(44^o)=y\implies \blacktriangleright 320.06 \approx y \blacktriangleleft[/tex]
