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A rectangle has an area of 717.8m2.
One of the sides is 7.4m in length.
Work out the perimeter of the rectangle.
please help me

Respuesta :

Answer:

The perimeter of the rectangle is [tex]208.8\ m[/tex]

Step-by-step explanation:

step 1

Find the width of the rectangle

we know that

The area of rectangle is equal to

[tex]A=LW[/tex]

we have

[tex]A=717.8\ m^{2}[/tex]

[tex]L=7.4\ m[/tex]

substitute and solve for W

[tex]717.8=7.4W[/tex]

[tex]W=717.8/7.4=97\ m[/tex]

step 2

Find the perimeter

The perimeter of rectangle is equal to

[tex]P=2(L+W)[/tex]

we have

[tex]W=97\ m[/tex]

[tex]L=7.4\ m[/tex]

substitute

[tex]P=2(7.4+97)=208.8\ m[/tex]