q = mass water (g) * specific of water heat water *delta T.
q = energy (in Joules, "J").
specific heat of water = 4.184 J/g*C (look up value) at 25.0 degrees C.
"delta T" = change of temperate change of the water
= T final - T initial (that is, final temperature minus initial temperature
We are given: 25.0 degrees C (ambient temperature).
Density of water at 25 degrees C = approx 1 g / ml ---->
so, 25 ml *(1 g/ml) = approx 25 g.
Q = (25 g water) *(4.184 J/g*C)* (26.4 C - 25.0 C)
= (25 g water) *(4.184 J/g*C)* (1.40 C)
= 146.44 --> round to 146 J
