Answer:
Step-by-step explanation:
The variable t is missing in the given equation as it should read:
ℎ(t)= −4.92t^2 + 3.28t + 1.7
When the ball will hit the ground, h=0
−4.92t^2 + 3.28t + 1.7 = 0
Using the quadratic formula to find the solution,
t = -0.34 or 1.01
As time cannot be negative, h=0 when t=1.01s. So Ana is correct.
Answer:
The answer is very close, within the margin of error.
Step-by-step explanation:
When the ball hits the ground, h(t) will equal 0
0 = −4.92t^2 + 3.28t +1.7
Using the quadratic equation
-b ± sqrt(b^2 -4ac)
------------------------------
2a
where a = -4.92 b = 3.28 and c = 1.7
-3.28 ± sqrt(3.28^2 -4(-4.92)1.7)
------------------------------
2(-4.92)
t≈-0.342418
t≈1.00908
The answer is very close, within the margin of error.
